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Topic 2/3
15 Flashcards in this deck.
The median is the middle value in a data set when the numbers are arranged in ascending or descending order. It divides the data into two equal halves. For an odd number of observations, the median is the central number. For an even number, it is the average of the two central numbers.
Formula:
For an ordered data set with an odd number of observations:
$$\text{Median} = \text{Middle value}$$For an even number of observations:
$$\text{Median} = \frac{\text{Value at position } \frac{n}{2} + \text{Value at position } \left(\frac{n}{2} + 1\right)}{2}$$Example:
Consider the data set: 3, 7, 8, 5, 12, 14, 21, 13, 18
Arranged in order: 3, 5, 7, 8, 12, 13, 14, 18, 21
Median = 12 (the fifth value in a nine-number data set)
Quartiles divide a ranked data set into four equal parts. The three quartiles (Q1, Q2, Q3) represent the 25th, 50th, and 75th percentiles, respectively.
First Quartile (Q1): The median of the lower half of the data (25th percentile).
Second Quartile (Q2): The median of the data set (50th percentile).
Third Quartile (Q3): The median of the upper half of the data (75th percentile).
Example:
Using the previous data set: 3, 5, 7, 8, 12, 13, 14, 18, 21
Q1 = 5 (median of 3, 5, 7, 8)
Q2 = 12 (median of the entire data set)
Q3 = 14 (median of 12, 13, 14, 18, 21)
Percentiles indicate the relative standing of a value within a data set. The nth percentile is the value below which n percent of the data fall.
Formula to find the percentile rank:
$$P = \left(\frac{b + \frac{c}{d}}{N}\right) \times 100$$Where:
Example:
Find the 40th percentile in the data set: 3, 5, 7, 8, 12, 13, 14, 18, 21
N = 9
P = 40
Position = $\frac{40}{100} \times (9 + 1) = 4$
The 4th value is 8, so the 40th percentile is 8.
The interquartile range measures the spread of the middle 50% of the data. It is the difference between the third quartile (Q3) and the first quartile (Q1).
Formula:
$$\text{IQR} = Q3 - Q1$$Example:
Using the previous quartiles: Q3 = 14 and Q1 = 5
IQR = 14 - 5 = 9
To determine these measures, follow these steps:
Example:
Data set: 7, 15, 36, 39, 40, 41
Step 1: Ordered data: 7, 15, 36, 39, 40, 41
Step 2: Median (Q2) = (36 + 39)/2 = 37.5
Step 3: Lower half: 7, 15, 36 → Q1 = 15
Step 4: Upper half: 39, 40, 41 → Q3 = 40
Step 5: IQR = 40 - 15 = 25
Step 6: To find the 90th percentile, Position = 0.9 * (6 + 1) = 6.3
The 90th percentile is between the 6th value (41) and the 7th value (not present), so it is approximately 41.
The measures of median, quartiles, percentiles, and interquartile range are crucial for understanding data distribution without being affected by outliers. Unlike the mean, which can be skewed by extreme values, the median provides a better central location for skewed distributions.
Mathematical Derivation of Quartiles:
For a data set with an odd number of observations, the quartiles are determined by the median of the lower and upper halves. For an even number, they are the medians of the divided data.
The calculation of percentiles can be approached using linear interpolation, especially when the desired percentile falls between two data points.
Proof of IQR Robustness:
The IQR is less sensitive to outliers compared to the range. Since it only considers the middle 50% of the data, extreme values do not influence it, making it a reliable measure of variability.
Problem 1: A data set consists of the following ages of participants in a workshop: 22, 27, 29, 31, 35, 38, 40, 42, 45, 48, 50, 52. Calculate the median, Q1, Q3, IQR, and the 85th percentile.
Solution:
Ordered data: 22, 27, 29, 31, 35, 38, 40, 42, 45, 48, 50, 52
N = 12 (even number)
Median (Q2) = (35 + 38)/2 = 36.5
Lower half: 22, 27, 29, 31, 35, 38 → Q1 = (29 + 31)/2 = 30
Upper half: 38, 40, 42, 45, 48, 50, 52 → Q3 = (42 + 45)/2 = 43.5
IQR = 43.5 - 30 = 13.5
85th percentile position = 0.85 * (12 + 1) = 11.05
85th percentile ≈ 48 + 0.05*(50 - 48) = 48 + 0.1 = 48.1
These statistical measures are not confined to mathematics but are extensively used in various fields:
When dealing with large data sets or grouped data, the calculation of medians, quartiles, and percentiles requires formulas to estimate their values accurately.
Grouped Data: For data presented in frequency tables, the median, quartiles, and percentiles can be found using interpolation within the appropriate class intervals.
Software Applications: Statistical software and programming languages like R and Python provide functions to calculate these measures efficiently, especially for extensive datasets.
In skewed distributions, the median provides a better central location than the mean. The distance between Q1, Q2 (median), and Q3 can indicate the direction and degree of skewness.
Positive Skew: Q3 - Q2 > Q2 - Q1
Negative Skew: Q2 - Q1 > Q3 - Q2
Understanding skewness is essential in fields like finance for risk assessment and in quality control for process improvement.
Measure | Definition | Use Case |
Median | The middle value of an ordered data set | Identifying the central tendency in skewed distributions |
Quartiles | Values that divide data into four equal parts | Analyzing the spread and identifying outliers |
Percentiles | Values below which a certain percent of data falls | Assessing individual performance relative to a group |
Interquartile Range (IQR) | Difference between Q3 and Q1 | Measuring data variability and identifying outliers |
To easily remember quartile positions, think of Q1 as the first quarter, Q2 as the second quarter (median), and Q3 as the third quarter. When calculating percentiles, practice using linear interpolation to estimate values accurately. For the AP exam, familiarize yourself with both manual calculation methods and statistical software tools to efficiently handle large data sets.
Did you know that the concept of quartiles dates back to the early 19th century, developed by American engineer and mathematician Francis Galton? Quartiles are not only fundamental in statistics but are also used in financial markets to analyze stock performance and in public health to assess the distribution of health indicators across populations.
Mistake 1: Confusing median with mean.
Incorrect: Assuming the average of numbers represents the central value.
Correct: Arrange the data and identify the middle value.
Mistake 2: Incorrectly dividing data sets when finding quartiles.
Incorrect: Including the median in both lower and upper halves for an odd number of observations.
Correct: Exclude the median when the number of observations is odd.
Mistake 3: Misapplying the percentile formula.
Incorrect: Using the wrong position formula leading to inaccurate percentiles.
Correct: Apply the correct formula: $P = \left(\frac{b + \frac{c}{d}}{N}\right) \times 100$.